3.1.70 \(\int (a \csc (e+f x))^m (b \csc (e+f x))^n \, dx\) [70]

Optimal. Leaf size=91 \[ \frac {a \cos (e+f x) (a \csc (e+f x))^{-1+m} (b \csc (e+f x))^n \, _2F_1\left (\frac {1}{2},\frac {1}{2} (1-m-n);\frac {1}{2} (3-m-n);\sin ^2(e+f x)\right )}{f (1-m-n) \sqrt {\cos ^2(e+f x)}} \]

[Out]

a*cos(f*x+e)*(a*csc(f*x+e))^(-1+m)*(b*csc(f*x+e))^n*hypergeom([1/2, 1/2-1/2*m-1/2*n],[3/2-1/2*m-1/2*n],sin(f*x
+e)^2)/f/(1-m-n)/(cos(f*x+e)^2)^(1/2)

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Rubi [A]
time = 0.03, antiderivative size = 91, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {20, 3857, 2722} \begin {gather*} \frac {a \cos (e+f x) (a \csc (e+f x))^{m-1} (b \csc (e+f x))^n \, _2F_1\left (\frac {1}{2},\frac {1}{2} (-m-n+1);\frac {1}{2} (-m-n+3);\sin ^2(e+f x)\right )}{f (-m-n+1) \sqrt {\cos ^2(e+f x)}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a*Csc[e + f*x])^m*(b*Csc[e + f*x])^n,x]

[Out]

(a*Cos[e + f*x]*(a*Csc[e + f*x])^(-1 + m)*(b*Csc[e + f*x])^n*Hypergeometric2F1[1/2, (1 - m - n)/2, (3 - m - n)
/2, Sin[e + f*x]^2])/(f*(1 - m - n)*Sqrt[Cos[e + f*x]^2])

Rule 20

Int[(u_.)*((a_.)*(v_))^(m_)*((b_.)*(v_))^(n_), x_Symbol] :> Dist[b^IntPart[n]*((b*v)^FracPart[n]/(a^IntPart[n]
*(a*v)^FracPart[n])), Int[u*(a*v)^(m + n), x], x] /; FreeQ[{a, b, m, n}, x] &&  !IntegerQ[m] &&  !IntegerQ[n]
&&  !IntegerQ[m + n]

Rule 2722

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*((b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1
)*Sqrt[Cos[c + d*x]^2]))*Hypergeometric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2], x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rule 3857

Int[(csc[(c_.) + (d_.)*(x_)]*(b_.))^(n_), x_Symbol] :> Simp[(b*Csc[c + d*x])^(n - 1)*((Sin[c + d*x]/b)^(n - 1)
*Int[1/(Sin[c + d*x]/b)^n, x]), x] /; FreeQ[{b, c, d, n}, x] &&  !IntegerQ[n]

Rubi steps

\begin {align*} \int (a \csc (e+f x))^m (b \csc (e+f x))^n \, dx &=\left ((a \csc (e+f x))^{-n} (b \csc (e+f x))^n\right ) \int (a \csc (e+f x))^{m+n} \, dx\\ &=\left ((a \csc (e+f x))^m (b \csc (e+f x))^n \left (\frac {\sin (e+f x)}{a}\right )^{m+n}\right ) \int \left (\frac {\sin (e+f x)}{a}\right )^{-m-n} \, dx\\ &=\frac {\cos (e+f x) (a \csc (e+f x))^m (b \csc (e+f x))^n \, _2F_1\left (\frac {1}{2},\frac {1}{2} (1-m-n);\frac {1}{2} (3-m-n);\sin ^2(e+f x)\right ) \sin (e+f x)}{f (1-m-n) \sqrt {\cos ^2(e+f x)}}\\ \end {align*}

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Mathematica [A]
time = 0.16, size = 77, normalized size = 0.85 \begin {gather*} -\frac {\cos (e+f x) (a \csc (e+f x))^m (b \csc (e+f x))^n \, _2F_1\left (\frac {1}{2},\frac {1}{2} (1+m+n);\frac {3}{2};\cos ^2(e+f x)\right ) \sin (e+f x) \sin ^2(e+f x)^{\frac {1}{2} (-1+m+n)}}{f} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a*Csc[e + f*x])^m*(b*Csc[e + f*x])^n,x]

[Out]

-((Cos[e + f*x]*(a*Csc[e + f*x])^m*(b*Csc[e + f*x])^n*Hypergeometric2F1[1/2, (1 + m + n)/2, 3/2, Cos[e + f*x]^
2]*Sin[e + f*x]*(Sin[e + f*x]^2)^((-1 + m + n)/2))/f)

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Maple [F]
time = 0.06, size = 0, normalized size = 0.00 \[\int \left (a \csc \left (f x +e \right )\right )^{m} \left (b \csc \left (f x +e \right )\right )^{n}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*csc(f*x+e))^m*(b*csc(f*x+e))^n,x)

[Out]

int((a*csc(f*x+e))^m*(b*csc(f*x+e))^n,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*csc(f*x+e))^m*(b*csc(f*x+e))^n,x, algorithm="maxima")

[Out]

integrate((a*csc(f*x + e))^m*(b*csc(f*x + e))^n, x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*csc(f*x+e))^m*(b*csc(f*x+e))^n,x, algorithm="fricas")

[Out]

integral((a*csc(f*x + e))^m*(b*csc(f*x + e))^n, x)

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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (a \csc {\left (e + f x \right )}\right )^{m} \left (b \csc {\left (e + f x \right )}\right )^{n}\, dx \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*csc(f*x+e))**m*(b*csc(f*x+e))**n,x)

[Out]

Integral((a*csc(e + f*x))**m*(b*csc(e + f*x))**n, x)

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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((a*csc(f*x+e))^m*(b*csc(f*x+e))^n,x, algorithm="giac")

[Out]

integrate((a*csc(f*x + e))^m*(b*csc(f*x + e))^n, x)

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int {\left (\frac {a}{\sin \left (e+f\,x\right )}\right )}^m\,{\left (\frac {b}{\sin \left (e+f\,x\right )}\right )}^n \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a/sin(e + f*x))^m*(b/sin(e + f*x))^n,x)

[Out]

int((a/sin(e + f*x))^m*(b/sin(e + f*x))^n, x)

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